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AP EAMCET · Maths · Application of Derivatives

By neglecting \(x^4\) and higher powers of \(x\), find approximate value of \(\sqrt[3]{x^2+64}-\sqrt[3]{x^2+27}\)

  1. A \(1-\frac{7}{234} x^2\)
  2. B \(1-\frac{7}{432} x^2\)
  3. C \(1-\frac{7}{32} x^2\)
  4. D \(1-\frac{7}{42} x^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1-\frac{7}{432} x^2\)

Step-by-step Solution

Detailed explanation

Given expression \(\begin{aligned} \sqrt[3]{x^2+64}-\sqrt[3]{x^2+27} & =4\left(1+\frac{x^2}{64}\right)^{1 / 3}-3\left(1+\frac{x^2}{27}\right)^{1 / 3} \\ & =4\left[1+\frac{x^2}{3 \times 64}\right]-3\left[1+\frac{x^2}{3 \times 27}\right] \end{aligned}\) \{on neglecting \(x^4\) and…