AP EAMCET · Maths · Probability
An electronic assembly consists of two subsystems \(A\) and \(B\). Past testing procedures data show that probabilities of failure are \(P(A\) fails \()=0.2, P(B\) fails alone \()=0.15\), \(P(A \& B\) fail \()=0.15\). Then the probability that \(A\) fails alone is equal to
- A \(0.02\)
- B \(0.03\)
- C \(0.04\)
- D \(0.05\)
Answer & Solution
Correct Answer
(D) \(0.05\)
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