AP EAMCET · Maths · Binomial Theorem
The coefficient of \(x^{50}\) in the expansion of \((1+x)^{100}+2 x(1+x)^{99}+3 x^2(1+x)^{98}+\) \(+101 x^{100}\), is
- A \({ }^{100} \mathrm{C}_{50}\)
- B \({ }^{101} \mathrm{C}_{50}\)
- C \({ }^{102} \mathrm{C}_{50}\)
- D \({ }^{103} \mathrm{C}_{50}\)
Answer & Solution
Correct Answer
(C) \({ }^{102} \mathrm{C}_{50}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Let } S=(1+x)^{100}+2 x(1+x)^{99}+3 x^2(1+x)^{98} \\ & +\ldots+101 x^{100} \\ & \frac{x}{1+x} S= \\ & x(1+x)^{99}+2 x^2(1+x)^{98}+\ldots+100 x^{100}+101 \frac{x^{101}}{1+x} \\ & \Rightarrow \frac{S}{1+x}=(1+x)^{100}+x(1+x)^{99}+x^2(1+x)^{98} \\ &…
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