AP EAMCET · Maths · Indefinite Integration
If \(\int \sqrt[3]{x}\left\{1+\sqrt[3]{x^4}\right\}^{1 / 7} d x=A\left(1+\sqrt[3]{x^4}\right)^B+c\), then value of \(A B\) is equal to
- A \(3 / 2\)
- B \(3 / 4\)
- C \(3 / 32\)
- D \(4 / 3\)
Answer & Solution
Correct Answer
(B) \(3 / 4\)
Step-by-step Solution
Detailed explanation
\(\int \sqrt[3]{x}\left\{1+\sqrt[3]{x^4}\right\}^{\frac{1}{7}} d x=A\left(1+\sqrt[3]{x^4}\right)^B+c\) Let us assume \[ I=\int \sqrt[3]{x}\left(1+\sqrt[3]{x^4}\right)^{\frac{1}{7}}=\int x^{\frac{1}{3}}\left(1+x^{\frac{4}{3}}\right)^{\frac{1}{7}} d x \]…
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