AP EAMCET · Maths · Application of Derivatives
The point on the curve \(x^2+y^2=a^2, y \geq 0\), at which the tangent is parallel to the \(x\)-axis is
- A \((a, 0)\)
- B \((-a, 0)\)
- C \((0, a)\)
- D \((0,-a)\)
Answer & Solution
Correct Answer
(C) \((0, a)\)
Step-by-step Solution
Detailed explanation
We have, \(x^2+y^2=a^2\) \(\Rightarrow \quad 2 x+2 y \frac{d y}{d x}=0 \Rightarrow \frac{d y}{d x}=\frac{-x}{y}\) Tangent is parallel to \(X\)-axis. \(\therefore \quad \frac{d y}{d x}=0\) \(\Rightarrow \quad \frac{-x}{y}=0 ; \therefore x=0\) Putting the value of \(x\) in…
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