AP EAMCET · Maths · Indefinite Integration
If \(\int \frac{2 \cos x+3 \sin x}{4 \cos x+5 \sin x} d x=\left(\frac{23}{41}\right) x+K \log\)
\(|4 \cos x+5 \sin x|+c\), then \(K\) is equal to
- A \(\frac{2}{41}\)
- B \(\frac{-2}{41}\)
- C \(\frac{3}{41}\)
- D \(\frac{-3}{41}\)
Answer & Solution
Correct Answer
(B) \(\frac{-2}{41}\)
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} \int \frac{2 \cos x+3 \sin x}{4 \cos x+5 \sin x} & =\frac{23}{41} x \\ & +K \log |4 \cos x+5 \sin x|+C \end{aligned} \] On differentiating, we get…
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