AP EAMCET · Maths · Circle
The locus of the point of intersection of perpendicular tangents drawn to the circle \(x^2+y^2=10\) is
- A \(x^2+y^2=5\)
- B \(x^2+y^2=20\)
- C \(x^2+y^2=25\)
- D \(x^2+y^2=100\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2=20\)
Step-by-step Solution
Detailed explanation
Locus of points of intersection of perpendicular tangents is the director circle. Given circle is \(x^2+y^2=10\). \(\therefore\) Director circle is \(x^2+y^2=20\) is the required locus.
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