AP EAMCET · Maths · Properties of Triangles
In \(\triangle A B C\),
\((a-b)^2 \sin ^2\left(\frac{A+B}{2}\right)+(a+b)^2 \sin ^2\left(\frac{C}{2}\right)=\)
- A \(b^2\)
- B \(a^2\)
- C \(c^2\)
- D \(a^2+b^2-c^2\)
Answer & Solution
Correct Answer
(C) \(c^2\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { In } \triangle A B C, A+B+C=\pi \\ & \qquad A+B=\pi-C \\ & =(a-b)^2 \sin ^2\left(\frac{A+B}{2}\right)+(a+b)^2 \sin ^2 \frac{C}{2} \\ & =\left[a^2+b^2-2 a b\right] \sin ^2\left(\frac{\pi-C}{2}\right) \\ & +\left[a^2+b^2+2 a b\right] \sin ^2…
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