AP EAMCET · Chemistry · p Block Elements (Group 13 & 14)
\(\mathrm{BF}_3\) reacts with \(\mathrm{NaH}\) at \(450 \mathrm{~K}\) to form \(\mathrm{NaF}\) and \(X\). When \(X\) reacts with \(\mathrm{LiH}\) in diethyl ether, \(Y\) is formed. What is \(Y\) ?
- A \(\mathrm{LiBO}_2\)
- B \(\mathrm{Li}_2 \mathrm{~B}_4 \mathrm{O}_7\)
- C \(\mathrm{LiBH}_4\)
- D \(\mathrm{B}_2 \mathrm{H}_6 \cdot \mathrm{LiH}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{LiBH}_4\)
Step-by-step Solution
Detailed explanation
\(2 \mathrm{BF}_3+6 \mathrm{NaH} \stackrel{450 \mathrm{~K}}{\longrightarrow} 6 \mathrm{NaF}+\mathrm{B}_2 \mathrm{H}_6(X)\) \(\mathrm{B}_2 \mathrm{H}_6+2 \mathrm{LiH} \stackrel{\text { Diethyl ether }}{\longrightarrow} 2 \mathrm{LiBH}_4(Y)\) Diborane Lithium boron hydride
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