AP EAMCET · Maths · Circle
Equation of the circle having its centre on the line \(2 x+y\) \(+3=0\) and having the lines \(3 x+4 y-18=0,3 x+4 y+2=\) 0 as tangents is
- A \(x^2+y^2+6 x+8 y+4=0\)
- B \(x^2+y^2-6 x-8 y+18=0\)
- C \(x^2+y^2-8 x+10 y+37=0\)
- D \(x^2+y^2+8 x-10 y+37=0\)
Answer & Solution
Correct Answer
(D) \(x^2+y^2+8 x-10 y+37=0\)
Step-by-step Solution
Detailed explanation
Equations of tangents \(\Rightarrow 3 x+4 y-18=0 \Rightarrow 3 x+4 y+2=0\) Since slope of tangents are equal. So tangents are parallel. And distance between two parallel lines is \(d=\frac{\left|c_2-c_1\right|}{\sqrt{a^2+b^2}}=\frac{20}{5}=4 \Rightarrow\) Radius…
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