AP EAMCET · Maths · Parabola
The distance of the point \((6,4 \sqrt{3})\) from the focus of \(y^2=8 x\) is
- A \(64\)
- B \(4\)
- C \(8\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
For \(y^2=8 x \quad\left(y^2=4 a x\right)\) Focus is \((a, 0) \equiv(2,0)\) distance of \((6,4 \sqrt{3})\) from \((2,0)=\) \(\sqrt{(6-2)^2+(4 \sqrt{3})^2}=\sqrt{16+48}\) \(\begin{aligned} & =\sqrt{64} \\ & =8\end{aligned}\)
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