AP EAMCET · Maths · Quadratic Equation
The sum of the fourth powers of the roots of the equation \(16 \mathrm{x}^2-10 \mathrm{x}+1=0\) is
- A \(\frac{257}{4096}\)
- B \(\frac{257}{2048}\)
- C \(\frac{257}{1024}\)
- D \(\frac{257}{512}\)
Answer & Solution
Correct Answer
(A) \(\frac{257}{4096}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {} 16 \mathrm{x}^2-10 \mathrm{x}+1=0 \\ & \Rightarrow 16 \mathrm{x}^2-8 \mathrm{x}-2 \mathrm{x}+1=0 \\ & \Rightarrow(2 \mathrm{x}-1)(8 \mathrm{x}-1)=0 \\ & \Rightarrow \mathrm{x}=\frac{1}{2}, \frac{1}{8} \\ &…
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