AP EAMCET · Maths · Quadratic Equation
\(\begin{aligned} & \frac{x^2+1}{x^4+4}=\frac{A x+B}{x^2-2 x+2}+\frac{C x+D}{x^2+2 x+2} \\ & \Rightarrow 3 A+2 B+3 C=\end{aligned}\)
- A \(-D\)
- B \(D\)
- C \(2 D\)
- D \(-2 D\)
Answer & Solution
Correct Answer
(C) \(2 D\)
Step-by-step Solution
Detailed explanation
\(\frac{x^2+1}{x^4+4}=\frac{A x+B}{x^2-2 x+2}+\frac{C x+D}{x^2+2 x+2}\) \(\Rightarrow \frac{x^2+1}{x^4+4}\) \(=\frac{(A x+B)\left(x^2+2 x+2\right)+(C x+D)\left(x^2-2 x+2\right)}{\left(x^2+2\right)^2-(2 x)^2}\) \(\Rightarrow x^2+1=(A+C) x^3+(2 A+B-2 C+D) x^2\)…
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