AP EAMCET · Maths · Circle
If the inverse point of the point \((-1,1)\) with respect to the circle \(x^2+y^2-2 x+2 y-1=0\) is \((p, q)\), then \(p^2+q^2=\)
- A \(\frac{1}{16}\)
- B \(\frac{1}{8}\)
- C \(\frac{1}{4}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{8}\)
Step-by-step Solution
Detailed explanation
The equation of pole w.r.t. point \((-1,1)\) to the circle \(x^2+y^2-2 x+2 y-1=0\) is \(\begin{aligned} & -x+y-(x-1)+(y+1)-1=0 \\ & \Rightarrow 2 x-2 y=1 \end{aligned}\) Since, inverse point of \((-1,1)\) is foot of the perpendicular from \((-1,1)\) to the line \(2 x-2 y-1=0\)…
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