AP EAMCET · Maths · Definite Integration
\(\int_0^{\frac{\pi}{2}} \frac{\sum_{n=0}^4\left(\frac{n \pi}{4}+x\right)}{\cos x+\sin x} d x=\)
- A \(I=\frac{15 \pi}{2 \sqrt{2}} \log |\sqrt{2}+1|\)
- B \(\frac{\pi}{2 \sqrt{2}}\)
- C \(\frac{3 \pi}{\sqrt{2}}\)
- D \((\sqrt{2}+1) \frac{\pi}{4}\)
Answer & Solution
Correct Answer
(A) \(I=\frac{15 \pi}{2 \sqrt{2}} \log |\sqrt{2}+1|\)
Step-by-step Solution
Detailed explanation
Let \(f=\int_0^{\frac{\pi}{2}} \frac{\sum_{n=0}^4 \frac{\pi \pi}{4}+x}{\cos x+\sin x} d r\) \(\operatorname{since} \sum_{x=1}^4\left(\frac{\operatorname{ex}}{4}+x\right)=(0+1+2+3+4) \frac{\pi}{4}+(1+1+1+1+1) x\) \(=\frac{5 \pi}{2}+5 x=5\left(\frac{\pi}{2}+x\right)\) Hence,…
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