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AP EAMCET · Maths · Functions

Let \(f: R \rightarrow R\) be defined by \(f(x)=2 x+3\). If \(\alpha\), \(\beta\) are the roots of the equation \(f\left(x^2\right)-2 f\left(\frac{x}{2}\right)-1=0\), then \(\alpha^2+\beta^2=\)

  1. A \(13\)
  2. B \(25\)
  3. C \(5\)
  4. D \(18\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(5\)

Step-by-step Solution

Detailed explanation

\begin{array}{rlrl} & & f(x)=2 x+3 \\ & & f\left(x^2\right)-2 f\left(\frac{x}{2}\right)-1=0 \\ \Rightarrow & 2 x^2+3-2(x+3)-1=0 \\ \Rightarrow & & 2 x^2-2 x-4=0 \\ \Rightarrow & & x^2-x-2=0 \\ \Rightarrow & & x=2 \text { or } x=-1 \\ \therefore & &…