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AP EAMCET · Maths · Quadratic Equation

Let \(\alpha, \beta\) be the roots of the equation \(x^2-|a| x-|b|=0\) such that \(|\alpha| < |\beta|\). If \(|a| < \beta-1\), then the positive root of \(\log _{\mid \text {여 }}\left(\frac{x^2}{\beta^2}\right)-1=0\), is

  1. A \( < |\alpha|\)
  2. B \( < \alpha\)
  3. C \( < \beta\)
  4. D \( > \beta\)
Verified Solution

Answer & Solution

Correct Answer

(D) \( > \beta\)

Step-by-step Solution

Detailed explanation

Given, \(\log _{|\alpha|}\left(\frac{x^2}{\beta^2}\right)=1\) \(\Rightarrow \quad \frac{x^2}{\beta^2}=|\alpha| \Rightarrow x^2=\beta^2|\alpha|\) and \(\alpha, \beta\) are roots of equation \(x^2-|a| x-|b|=0\)...(i) so,…