AP EAMCET · Maths · Probability
The mean and variance of a binomial distribution are 5 and 4 respectively. Then what is \(p(X=1)=\) ?
- A \(\frac{4^{24}}{5^{23}}\)
- B \(\frac{4^{24}}{5^{24}}\)
- C \(\frac{4}{5^{23}}\)
- D \(\frac{4}{5^{24}}\)
Answer & Solution
Correct Answer
(A) \(\frac{4^{24}}{5^{23}}\)
Step-by-step Solution
Detailed explanation
Mean of binomial distribution \(=5\) Variance of binomial distribution \(=4\) \(\Rightarrow n p=5\) and \(n p q=4\) Use \(n p=5\) in \(n p q=4\), we get (5)q \(q\) \[ \Rightarrow \quad q=4 / 5 \] Now, \(p=1-q=1-\frac{4}{5}=\frac{1}{5}\)…
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