AP EAMCET · Maths · Probability
Given that the probability of a man hitting a target with a gun is \(\frac{1}{3}\). If he fires 8 times, then the probability of his hitting the target atleast twice is
- A \(5\left(\frac{2}{3}\right)^8\)
- B \(1-5\left(\frac{2}{3}\right)^8\)
- C \(\left(\frac{2}{3}\right)^8\)
- D \(\left(\frac{3}{8}\right)^4\)
Answer & Solution
Correct Answer
(B) \(1-5\left(\frac{2}{3}\right)^8\)
Step-by-step Solution
Detailed explanation
Probability to hit the target \(=\frac{1}{3}\) Probability to not hit the target \(=1-\frac{1}{3}=\frac{2}{3}\) Probability to hit the target atleast twice is…
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