AP EAMCET · Maths · Three Dimensional Geometry
If \(\mathrm{a}, \mathrm{b}, \mathrm{c}\) are the intercepts made by the plane passing through the point \((1,2,3)\) parallel to the plane \(3 \mathrm{x}+4 \mathrm{y}-5 \mathrm{z}=0\) on \(\mathrm{X}, \mathrm{Y}, \mathrm{Z}\)-axes respectively then \(3 \mathrm{a}+\mathrm{b}+5 \mathrm{c}=\)
- A 0
- B 1
- C -1
- D 2
Answer & Solution
Correct Answer
(C) -1
Step-by-step Solution
Detailed explanation
Since a,b,c are intercepts made by the plane passin through the point \((1,2,3)\) \(\Rightarrow\) Let \(P_1=\frac{x}{a}+\frac{4}{b}+\frac{z}{c}=1\) Let \(P_2=3 x+4 y-5 z=0\) \(\because \mathrm{P}_2\) II \(\mathrm{P}_1\) and \(\mathrm{P}_1\) passing the \((1,2,3)\) now…
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