AP EAMCET · Maths · Straight Lines
If \(A(2,-3)\) and \(B(-2,1)\) are two vertices of a \(\triangle A B C\) and if the centroid of \(\triangle A B C\) lies on the line \(2 x+3 y=1\), then the locus of vertex \(C\) of \(\triangle A B C\) is equal to
- A \(2 x+3 y=5\)
- B \(2 x+3 y=9\)
- C \(3 x+2 y=5\)
- D \(3 x+2 y=9\)
Answer & Solution
Correct Answer
(D) \(3 x+2 y=9\)
Step-by-step Solution
Detailed explanation
Let third vertex be \(C=(h, k)\) \(\begin{aligned} A & \equiv(2,-3) \\ B & \equiv(-2,1) \end{aligned}\) Centroid \((G)=\left(\frac{h}{3}, \frac{-2+k}{3}\right)\) Since, given \(G\) lies on \(2 x+3 y=1\)…
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