AP EAMCET · PHYSICS · Work Power Energy
A spring has a spring constant \(200 \mathrm{Nm}^{-1}\). If it is stretched by \(1 \mathrm{~cm}\) then the potential energy stored in it is
- A \(100 \mathrm{~J}\)
- B \(0.01 \mathrm{~J}\)
- C \(10 \mathrm{~J}\)
- D \(1 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(0.01 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Spring constant, \(\mathrm{k}=200 \mathrm{~N} / \mathrm{m}\) Stretched length, \(x=1 \mathrm{~cm}=0.01 \mathrm{~m}\) Potential energy stored is given as:…
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