AP EAMCET · Maths · Determinants
If \(A\) is a matrix of order 3 whose determinant is equal to 6 , then \(\operatorname{det}(\operatorname{adj} A)=\)
- A \(6\)
- B \(36\)
- C \(216\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(36\)
Step-by-step Solution
Detailed explanation
\(\operatorname{det}(\operatorname{adj} A) = (\operatorname{det} A)^{n-1}\) \(\operatorname{det}(\operatorname{adj} A) = (6)^{3-1}\) \(\operatorname{det}(\operatorname{adj} A) = 6^2 = 36\)
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