AP EAMCET · Maths · Three Dimensional Geometry
A variable plane \(\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1\), which is at a unit distance from the origin cuts the coordinate axes at \(A, B\) and \(C\). If the centroid \((x, y, z)\) of \(\triangle A B C\) satisfies \(\frac{1}{x^2}+\frac{1}{y^2}+\frac{1}{z^2}=k\), then \(k\) equals
- A \(9\)
- B \(3\)
- C \(\frac{1}{9}\)
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(A) \(9\)
Step-by-step Solution
Detailed explanation
\(\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1\) which is unit distance from the origin cuts the coordinates axes at \(A, B\) and \(C\). \(\therefore \quad 1=\frac{1}{\sqrt{\frac{1}{a^2}+\frac{1}{b^2}+\frac{1}{c^2}}} \Rightarrow \frac{1}{a^2}+\frac{1}{b^2}+\frac{1}{c^2}=1\) Coordinate…
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