AP EAMCET · Maths · Inverse Trigonometric Functions
If \(2 \sin \mathrm{h}^{-1}\left(\frac{a}{\sqrt{1-a^2}}\right)=\log \left(\frac{1+x}{1-x}\right)\), then \(x\) is equal to
- A \(a\)
- B \(\frac{1}{a}\)
- C \(\sqrt{1-a^2}\)
- D \(\frac{1}{\sqrt{1-a^2}}\)
Answer & Solution
Correct Answer
(A) \(a\)
Step-by-step Solution
Detailed explanation
We have given, As we know, \(\sinh ^{-1} x=\log x+\sqrt{1+x^2}\) So, \(2 \sin \mathrm{h}^{-1} x=2 \log \left(x+\sqrt{1+x^2}\right)\)…
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