AP EAMCET · Maths · Quadratic Equation
If \(a x^2+b x+c < 0 \forall x \in \mathbb{R}\) and the expressions \(c x^2+a x+b\) and \(a x^2+b x+c\) have their extreme values at the same point \(x\), then for the expression \(c x^2+a x+b\)
- A Minimum value \(=\frac{4 b}{3}\)
- B Maximum value \(=\frac{4 a}{3}\)
- C Minimum value \(=\frac{3 a}{4}\)
- D Maximum value \(=\frac{3 \mathrm{~b}}{4}\)
Answer & Solution
Correct Answer
(D) Maximum value \(=\frac{3 \mathrm{~b}}{4}\)
Step-by-step Solution
Detailed explanation
\(-\frac{b}{2a} = -\frac{a}{2c} \) \(a^2 = bc \) From \(a x^2+b x+c For \(c x^2+a x+b\), since \(cMaximum value \( = \frac{4(c)(b) - a^2}{4c} \) \( = \frac{4cb - bc}{4c} \) \( = \frac{3bc}{4c} \) \( = \frac{3b}{4} \)
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