AP EAMCET · PHYSICS · Laws of Motion
A bullet of mass \(20 \mathrm{~g}\) moving with \(500 \mathrm{~ms}^{-1}\) is pierced \(1 \mathrm{~cm}\) into a wooden block, then the retarding force experienced by the bullet is
- A \(125 \times 10^3 \mathrm{~N}\)
- B \(750 \times 10^3 \mathrm{~N}\)
- C \(500 \times 10^3 \mathrm{~N}\)
- D \(250 \times 10^3 \mathrm{~N}\)
Answer & Solution
Correct Answer
(D) \(250 \times 10^3 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Mass, \(\mathrm{m}=20 \mathrm{~g}=20 \times 10^{-3} \mathrm{~kg}\) velocity, \(\mathrm{u}=500 \mathrm{~m} / \mathrm{s}\) distance, \(\mathrm{d}=1 \mathrm{~cm}=0.0 / \mathrm{m}\) final velocity, \(v=0\) Using Equation of Motion, \(v^2-u^2=2 a d\)…
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