AP EAMCET · Maths · Differentiation
If \(x^3+y^3=3 a x y\), then at \(\left(\frac{3 a}{2}, \frac{3 a}{2}\right)\) the value of \(3 a y^{\prime \prime}+40\) is
- A \(-5\)
- B \(0\)
- C \(8\)
- D \(1\)
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
\(x^3+y^3=3 a x y\) \(3 x^2+3 y^2 \frac{d y}{d x}=3 a y+3 a x \frac{d y}{d x}\)…
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