AP EAMCET · PHYSICS · Motion In One Dimension
The velocity of a particle is given by the, equation \(v(x)\) \(=3 x^2-4 x\), where ' \(x\) ' is the distance covered by the particle. The expression for its acceleration is
- A \((6 x-4)\)
- B \(6\left(3 x^2-4 x\right)\)
- C \(\left(3 x^2-4 x\right)(6 x-4)\)
- D \((6 x-4)^2\)
Answer & Solution
Correct Answer
(C) \(\left(3 x^2-4 x\right)(6 x-4)\)
Step-by-step Solution
Detailed explanation
Velocity, \(v=3 x^2-4 x\) \(\therefore \quad\) Acceleration, \(a=v \cdot \frac{d v}{d x}=\left(3 x^2-4 x\right) \frac{d}{d x}\left(3 x^2-4 x\right)\) \(=\left(3 x^2-4 x\right)(6 x-4)\)
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