AP EAMCET · Maths · Differential Equations
The general solution of the differential equation \(\left(x+2 y^3\right) \frac{d y}{d x}-y=0, y>0\) is
- A \(y=x^3+c y\)
- B \(x=y^3+c y\)
- C \(y(1-x y)=c x\)
- D \(x(1-x y)=c y\)
Answer & Solution
Correct Answer
(B) \(x=y^3+c y\)
Step-by-step Solution
Detailed explanation
\(\frac{d x}{d y} = \frac{x+2 y^3}{y}\) \(\frac{d x}{d y} - \frac{1}{y} x = 2 y^2\) Integrating factor: \(e^{\int -\frac{1}{y} dy} = e^{-\ln y} = \frac{1}{y}\) \(x \cdot \frac{1}{y} = \int 2 y^2 \cdot \frac{1}{y} dy\) \(\frac{x}{y} = \int 2 y dy\) \(\frac{x}{y} = y^2 + c\)…
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