AP EAMCET · Maths · Circle
If \((1, a),(b, 2)\) are conjugate points with respect to the circle \(x^2+y^2=25\), then \(4 a+2 b=\)
- A 25
- B 50
- C 75
- D 100
Answer & Solution
Correct Answer
(B) 50
Step-by-step Solution
Detailed explanation
The condition for conjugate points \((x_1, y_1)\) and \((x_2, y_2)\) with respect to \(x^2+y^2=R^2\) is \(x_1 x_2 + y_1 y_2 = R^2\). \((1)(b) + (a)(2) = 25\) \(b + 2a = 25\) \(4a + 2b = 2(2a + b)\) \(4a + 2b = 2(25)\) \(4a + 2b = 50\)
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