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AP EAMCET · Maths · Ellipse

If the tangent at the point \(\left(4 \cos 2 \theta, \frac{16}{\sqrt{11}} \sin 2 \theta\right)\) on the ellipse \(16 x^2+11 y^2=256\) touches the circle \(x^2+y^2-2 x=15\), then \(\theta=\)

  1. A \(\pm \frac{\pi}{3}\)
  2. B \(\pm \frac{\pi}{6}\)
  3. C \(\pm \frac{\pi}{4}\)
  4. D \(\pm \frac{\pi}{8}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\pm \frac{\pi}{6}\)

Step-by-step Solution

Detailed explanation

Equation of tangent at point \(\left(4 \cos 2 \theta, \frac{16}{\sqrt{11}} \sin 2 \theta\right)\) on the ellipse \(16 x^2+11 y^2=256\) is…