AP EAMCET · PHYSICS · Wave Optics
The angular deviation of 5 th order dark fringe is \(12^{\circ}\) in a single slit experiment. If the width of the slit is \(9 \mu \mathrm{m}\) then the wavelength of the incident light is
- A \(4862 Å\)
- B \(5892 Å\)
- C \(6002 Å\)
- D \(3768 Å\)
Answer & Solution
Correct Answer
(D) \(3768 Å\)
Step-by-step Solution
Detailed explanation
Given, angular deviation of 5th order dark fringe, \(\theta=12^{\circ}\), Width of the slit, \(d=9 \mu \mathrm{m}\) Now, angular deviation of \(n\)th fringe \(=n \cdot \frac{\lambda}{d}\)…
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