AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A steel sphere of radius 1.2 cm collides a second steel sphere at rest. If the collision is elastic and after the collision the first sphere continues to move in its initial direction with a velocity of \(\frac{7}{9}\) times its initial velocity, then the radius of the second sphere is
- A 1.8 cm
- B 2.4 cm
- C 1.2 cm
- D 0.6 cm
Answer & Solution
Correct Answer
(D) 0.6 cm
Step-by-step Solution
Detailed explanation
\(v_1' = \frac{m_1 - m_2}{m_1 + m_2} v_1\) \(\frac{7}{9} = \frac{m_1 - m_2}{m_1 + m_2}\) \(7(m_1 + m_2) = 9(m_1 - m_2) \Rightarrow 16m_2 = 2m_1 \Rightarrow m_1 = 8m_2\) \(m \propto R^3 \Rightarrow (R_1/R_2)^3 = m_1/m_2 = 8\) \((1.2 / R_2)^3 = 8 \Rightarrow 1.2 / R_2 = 2\)…
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