AP EAMCET · PHYSICS · Laws of Motion
Starting from rest, the time taken by a body sliding down on a rough inclined plane at \(45^{\circ}\) with the horizontal is, twice the time taken to travel on a smooth plane of same inclination and same distance. Then the coefficient of kinetic friction is
- A \(0.25\)
- B \(0.33\)
- C \(0.50\)
- D \(0.75\)
Answer & Solution
Correct Answer
(D) \(0.75\)
Step-by-step Solution
Detailed explanation
\[ \mu=\tan \theta\left[1-\frac{1}{n^2}\right] \] Here, \(\quad \theta=45^{\circ}\) and \(n=2\) \(\begin{aligned} \therefore \quad \mu & =\tan 45^{\circ}\left[1-\frac{1}{2^2}\right] \\ & =1-\frac{1}{4}=\frac{3}{4}=0.75\end{aligned}\)
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