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AP EAMCET · Maths · Limits

If \(a, b\) and \(c\) are three distinct real numbers and \(\lim _{x \rightarrow \infty} \frac{(b-c) x^2+(c-a) x+(a-b)}{(a-b) x^2+(b-c) x+(c-a)}=\frac{1}{2}\), then \(a+2 c=\)

  1. A \(b\)
  2. B \(2 b\)
  3. C \(3 b\)
  4. D \(4 b\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3 b\)

Step-by-step Solution

Detailed explanation

\(\lim _{x \rightarrow \infty} \frac{(b-c) x^2+(c-a) x+(a-b)}{(a-b) x^2+(b-c) x+(c-a)}=\frac{1}{a}\) \(=\lim _{x \rightarrow \infty} \frac{x^2}{x^2}\left[\frac{(b-c)+(c-a) \frac{1}{x}+\frac{(a-b)}{x^2}}{(a-b)+(b-c) \frac{1}{x}+\frac{(c-a)}{x^2}}\right]=\frac{1}{2}\)…