AP EAMCET · Maths · Probability
A bag \(X\) contains 2 white and 3 black balls and another bag \(Y\) contains 4 white and 2 black balls. One bag is selected at random and a ball is drawn from it. Then, the probability for the ball chosen be white, is :
- A \(\frac{2}{15}\)
- B \(\frac{7}{15}\)
- C \(\frac{8}{15}\)
- D \(\frac{14}{15}\)
Answer & Solution
Correct Answer
(C) \(\frac{8}{15}\)
Step-by-step Solution
Detailed explanation
Probability of selecting a white ball from \(X\) bag \(=\frac{2}{5}\) Probability of selecting a white ball from \(Y\) bag \(=\frac{4}{6}=\frac{2}{3}\) Probability of selecting a white ball from \(X\) or \(Y\) bags \(=\frac{2}{5}+\frac{2}{3}=\frac{6+10}{15}=\frac{16}{15}\)…
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