AP EAMCET · Maths · Straight Lines
The orthocentre of the triangle formed by lines \(x+y+1=0 ; x-y-1=0\) and \(3 x+4 y+5=0\) is
- A \((0,-1)\)
- B \((0,0)\)
- C \((1,1)\)
- D \((-1,0)\)
Answer & Solution
Correct Answer
(A) \((0,-1)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & x+y+1=0 ...(i)\\ & x-y-1=0 ....(ii)\\ & 3 x+4 y+5=0 ....(iii) \end{aligned}\) Slope of (i) is -1 Slope of (ii) is 1 \(\therefore\) Triangle is right angled triangle and orthocentre of right angled triangle is the vertex where triangle has right angle. Solving…
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