ExamBro
ExamBro
AP EAMCET · Maths · Area Under Curves

Area of the region enclosed by the curves \(3 x^2-y^2-2 x y\) \(+4 x+1=0\) and \(3 x^2-y^2-2 x y+6 x+2 y=0\) is

  1. A \(\frac{3}{4}\)
  2. B \(\frac{1}{4}\)
  3. C 1
  4. D \(\frac{1}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{4}\)

Step-by-step Solution

Detailed explanation

Given equation of curve is \(\begin{aligned} & 3 x^2+(4-2 y) x+1-y^2=0 \\ & \therefore x=\frac{(2 y-4) \pm \sqrt{(4-2 y)^2-4 \times 3\left(1-y^2\right)}}{6} \\ & -\frac{2(y-2) \pm \sqrt{4(2 y-1)^2}}{6}=\frac{(y-2) \pm(2 y-1)}{3} \end{aligned}\) \(\therefore\) Equation of pair of…
From AP EAMCET
Explore more questions on app