AP EAMCET · Maths · Probability
Bag A contains 3 white and 4 red balls, bag B contains 4 white and 5 red balls and bag \(C\) contains 5 white and 6 red balls. If one ball is drawn at random from eath of these three bags, then the probability of getting one white and two red balls is
- A \(\frac{268}{693}\)
- B \(\frac{310}{693}\)
- C \(\frac{38}{99}\)
- D \(\frac{26}{63}\)
Answer & Solution
Correct Answer
(D) \(\frac{26}{63}\)
Step-by-step Solution
Detailed explanation
Bag \(A\) has 3 white and 4 red balls. Bag \(B\) has 4 white and 5 red balls. Bag \(C\) has 5 white and 6 red balls. Case I : Probability that white ball is from Bag \(A\) \(=\frac{3}{7} \times \frac{5}{9} \times \frac{6}{11}=\frac{90}{693}\) Case II : Probability that white…
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