AP EAMCET · PHYSICS · Magnetic Effects of Current
A charge ' \(q\) ' is spread uniformly over an isolated ring of radius ' \(R\) '. The ring is rotated about its natural axis with angular speed \(\omega\). The magnetic dipole moment of the ring is
- A \(\frac{q \omega R}{2}\)
- B \(q \omega R^2\)
- C \(\frac{q \omega R^2}{2}\)
- D \(\frac{q \omega}{2 R}\)
Answer & Solution
Correct Answer
(C) \(\frac{q \omega R^2}{2}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Magnetic moment, } \\ & M=\left(\frac{q}{2 m}\right) L \\ & =\left(\frac{q}{2 m}\right)\left(m R^2\right) \omega \\ & =\frac{q \omega R^2}{2}\end{aligned}\)
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