AP EAMCET · Chemistry · Structure of Atom
The de Broglie wavelength of an electron travelling with \(20 \%\) of velocity of light is
\(\left(\mathrm{h}=6.626 \times 10^{-34} \mathrm{JS} ; \mathrm{m}_{\mathrm{e}}=9.1 \times 10^{-31} \mathrm{~kg}\right)\)
- A \(2.4 \times 10^{-11} \mathrm{~m}\)
- B \(1.2 \times 10^{-11} \mathrm{~m}\)
- C \(3.6 \times 10^{-11} \mathrm{~m}\)
- D \(4.8 \times 10^{-11} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(1.2 \times 10^{-11} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{C}=3 \times 10^8 \mathrm{~ms}^{-1}\) \(\Rightarrow \operatorname{Velocity}(V)=\frac{20 \times 3 \times 10^8}{100}=6 \times 10^7 \mathrm{~ms}^{-1}\) Thus,…
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