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AP EAMCET · PHYSICS · Magnetic Effects of Current

The force acting per unit length when a very long straight conductor is carrying a steady current of \(1 \mathrm{~A}\) and the direction of the current is from south to north is
(The horizontal component of the earth's magnetic field at the place is \(3 \times 10^{-5} \mathrm{~T}\) and the direction of the field is from the geographical south to geographical north.)

  1. A \(3 \times 10^{-5} \mathrm{Nm}^{-1}\)
  2. B \(1 \times 10^{-5} \mathrm{Nm}^{-1}\)
  3. C 0
  4. D \(1.5 \times 10^{-5} \mathrm{Nm}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(3 \times 10^{-5} \mathrm{Nm}^{-1}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { Steady current, } \mathrm{i}=1 \mathrm{~A} \\ & \text { Magnetic field } \mathrm{B}=3 \times 10^{-5} \mathrm{~T} \\ & \mathrm{~F}=\mathrm{il} \times \mathrm{B}=\mathrm{ilB} \sin \theta \\ & \frac{\mathrm{F}}{1}=\mathrm{iB} \sin 90 \\ & =1 \times 3…