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AP EAMCET · Maths · Quadratic Equation

If α,β are the roots of 11x2+12x-13=0, then 1α2+1β2=? (approximately close to)

  1. A 4.54
  2. B 3.54
  3. C 2.54
  4. D 1.54
Verified Solution

Answer & Solution

Correct Answer

(C) 2.54

Step-by-step Solution

Detailed explanation

Given, 11x2+12x-13=0 Then, α+β=-1211 and αβ=-1311 Now, 1α2+1β2=α2+β2α2β2 =α+β2-2αβαβ2 Putting the values we get, =-12112-2-1311-13112 =1.19+2.361.39 ≈2.54