AP EAMCET · Chemistry · Electrochemistry
A hydrogen electrode is made by dipping platinum wire in a solution of nitric acid of \(\mathrm{pH}=9\) and passing hydrogen gas around the platinum wire at \(1.2 \mathrm{~atm}\) pressure. The oxidation potential of such an electrode equals .V.
- A 0.059
- B -0.0531
- C -0.059
- D 0.0531
Answer & Solution
Correct Answer
(D) 0.0531
Step-by-step Solution
Detailed explanation
For hydrogen electrode, oxidation half reaction is, \[ \underset{1.2 \mathrm{~atm}}{\mathrm{H}_2} \longrightarrow \underset{\text { (at pH 9) }}{2 \mathrm{H}^{+}}+2 e^{-} \] If \(\mathrm{pH}=9\) then \(\mathrm{H}^{+}\)ion \(=1 \times 10^{-\mathrm{pH}}=1 \times 10^{-9}\) Using…
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