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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

यदि समीकरणों के निकाय \(\alpha x+y+z=5\), \(x +2 y +3 z =4, x +3 y +5 z =\beta\) के अनन्त हल है तो क्रमित युग्म \((\alpha, \beta)\) का मान होगा:

  1. A \((1,-3)\)
  2. B \((-1,3)\)
  3. C \((1,3)\)
  4. D \((-1,-3)\)
Verified Solution

Answer & Solution

Correct Answer

(C) \((1,3)\)

Step-by-step Solution

Detailed explanation

For infinitely many solutions, \(\Delta=0=\Delta_{ x }=\Delta_{ y }=\Delta_{ z }\) \(\Delta=\left|\begin{array}{lll}\alpha & 1 & 1 \\ 1 & 2 & 3 \\ 1 & 3 & 5\end{array}\right|=0\) \(\Rightarrow \alpha(10-9)-1(5-3)+1(3-2)=0\) \(\Rightarrow \alpha-2+1=0\) \(\Rightarrow \alpha=1\)…
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