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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

यदि समीकरण \(( a -1)\left(x^{4}+x^{2}+1\right)+( a +1)\left(x^{2}+x+1\right)^{2}=0\) के दो मूल वास्तविक तथा विभित्र हैं, तो ' \(a\) ' के सभी मानों का समूह है

  1. A \(\left( {0\,,\,\frac{1}{2}} \right)\)
  2. B \(\left( {\, - \frac{1}{2}\,,\,0} \right) \cup \left( {0\,,\,\frac{1}{2}} \right)\)
  3. C \(\left( {\, - \frac{1}{2}\,,\,0} \right)\)
  4. D \(\left( { - \infty \,,\, - 2} \right) \cup \left( {2\,,\,\infty } \right)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\left( {\, - \frac{1}{2}\,,\,0} \right) \cup \left( {0\,,\,\frac{1}{2}} \right)\)

Step-by-step Solution

Detailed explanation

\((a-1)\left(x^{4}+x^{2}+1\right)\) \(+(a+1)\left(x^{2}+x+1\right)^{2}=0\) \(\Rightarrow(a-1)\left(x^{2}+x+1\right)\left(x^{2}-x+1\right)\) \(+(a+1)\left(x^{2}+x+1\right)^{2}=0\) \( \Rightarrow \left( {{x^2} + x + 1} \right)[(a - 1)\left( {{x^2} - x + 1} \right)\)…
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