ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 11. three dimension geometry

यदि रेखाओं \(\frac{\mathrm{x}-\lambda}{2}=\frac{\mathrm{y}-4}{3}=\frac{\mathrm{z}-3}{4}\) और \(\frac{x-2}{4}=\frac{y-4}{6}=\frac{z-7}{8}\) के बीच की न्यूनतम दूरी \(\frac{13}{\sqrt{29}}\) है, तो \(\lambda\) का एक मान ........... है।

  1. A  \(-\frac{13}{25}\)
  2. B \(\frac{13}{25}\)
  3. C \(1\)
  4. D \(-1\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1\)

Step-by-step Solution

Detailed explanation

Shortest dist. \(=\frac{\left|\overline{\mathrm{b}} \times\left(\overline{\mathrm{a}}_2-\overline{\mathrm{a}}_1\right)\right|}{|\mathrm{b}|}=\frac{13}{\sqrt{29}} \)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app