ExamBro
ExamBro
JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

वृत्त \((\mathrm{x}-\alpha)^2+(\mathrm{y}-\beta)^2=50\), जहाँ \(\alpha, \beta>0\) है, का विचार कीजिए। यदि यह वृत्त रेखा \(\mathrm{y}+\mathrm{x}=0\) की बिंदु \(P\) की मूल बिंदु से दूरी \(4 \sqrt{2}\) है, तो \((\alpha+\beta)^2\) = ...........

  1. A \(103\)
  2. B \(102\)
  3. C \(55\)
  4. D \(100\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(100\)

Step-by-step Solution

Detailed explanation

\( S:(x-\alpha)^2+(y-\beta)^2=50 \) \( C P=r \) \( \left|\frac{\alpha+\beta}{\sqrt{2}}\right|=5 \sqrt{2} \) \( \Rightarrow(\alpha+\beta)^2=100\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app