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JEE Mains · Maths · STD 12 - 6. Application of derivatives

समीकरण, \(e^{6 x }- e ^{4 x }-2 e ^{3 x }-12 e ^{2 x }+ e ^{ x }+1=0\) के वास्तविक मूलों की संख्या है

  1. A \(1\)
  2. B \(6\)
  3. C \(4\)
  4. D \(2\)
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Answer & Solution

Correct Answer

(D) \(2\)

Step-by-step Solution

Detailed explanation

\(e^{6 x}-e^{4 x}-2 e^{3 x}-12 e^{2 x}+e^{x}+1=0\) \(\Rightarrow\left(e^{3 x}-1\right)^{2}-e^{x}\left(e^{3 x}-1\right)=12 e^{2 x}\) \(\left(e^{3 x}-1\right)^{2}\left(e^{x}-e^{-x}-e^{-2 x}\right)=12\)…
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